CheckIO: Brackets

import re


def checkio(expression):
    pattern = '({}|\[\]|\(\))'
    matcher = re.compile(pattern)
    brackets = ''.join(x for x in expression if x in '{}[]()')
    while True:
        m = matcher.search(brackets)
        if not m: break
        brackets = brackets.replace(m.group(), '')
    return False if brackets else True
    
    
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio("((5+3)*2+1)") == True, "Simple"
    assert checkio("{[(3+1)+2]+}") == True, "Different types"
    assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
    assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
    assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
    assert checkio("2+3") == True, "No brackets, no problem"

https://www.checkio.org/mission/brackets/

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